ALGORITHMS/Student Engineering Notebook
Page 08·notes
GREEDY STRATEGIES & DYNAMIC PROGRAMMING—~34 MIN READ

Matrix Chain Multiplication & Optimization Problems

“Optimal parenthesization, Catalan number state space, O(n^3) table formulation, and DP on DAGs.”

1.The Matrix Chain Parenthesization Problem

Matrix multiplication is associative: (A_1 A_2) A_3 = A_1 (A_2 A_3). However, the order of parenthesization dramatically impacts the number of scalar multiplications.

For a chain of n matrices where matrix A_i has dimension p_{i-1} times p_i:

Let m[i, j] be the minimum number of scalar multiplications needed to compute the product A_i .. A_j.

The Recurrence:

m[i, j] = 0 if i = j

m[i, j] = min_{i <= k < j} { m[i, k] + m[k+1, j] + p_{i-1} p_k p_j } if i < j.

Because computing m[i, j] requires values of smaller chain lengths, the table is filled diagonally by chain length l = 2, 3, ..., n.

Complexity: Theta(n^3) time and Theta(n^2) space.

2.DAG Shortest/Longest Paths & Held-Karp TSP

Dynamic Programming on DAGs:

Because a Directed Acyclic Graph has no cycles, vertices can be linearized into a topological sort v_1, v_2, ..., v_n.

For longest path in a DAG:

dist[v] = max_{(u, v) in E} { dist[u] + w(u, v) }.

Evaluating in topological order ensures every subproblem dist[u] is finalized before computing dist[v]. Running time: O(V + E). Works with negative edge weights!

Held-Karp TSP Algorithm:

Brute force TSP checks (n - 1)! tours. Using DP:

Let C(S, j) be the minimum cost of visiting every vertex in subset S exactly once, starting at vertex 1 and ending at vertex j in S.

C(S, j) = min_{i in S setminus {j}} { C(S setminus {j}, i) + dist(i, j) }.

Time complexity: O(n^2 2^n), space O(n 2^n).

WORKED EXAM ANALYSIS · STEP-BY-STEP DERIVATIONOriginal Practice Problem · Modeled on GATE Pattern (2 Marks)

3. Worked Problem: 4-Matrix Optimal Parenthesization Table

⚠️ Pitfall Warning:

Ensure dimensions array p corresponds to matrix A_i having size p_{i-1} x p_i.

Problem: Find minimum scalar multiplications to multiply 4 matrices with dimensions: A1 (10x20), A2 (20x30), A3 (30x40), A4 (40x30). Dimension vector p = [10, 20, 30, 40, 30].

Step 1: Compute chain lengths of 2 (l = 2):

M[1, 2] = 10 20 30 = 6,000 (split k = 1)

M[2, 3] = 20 30 40 = 24,000 (split k = 2)

M[3, 4] = 30 40 30 = 36,000 (split k = 3)

Step 2: Compute chain lengths of 3 (l = 3):

M[1, 3] = min(

k=1: M[1,1] + M[2,3] + 102040 = 0 + 24000 + 8000 = 32000,

k=2: M[1,2] + M[3,3] + 103040 = 6000 + 0 + 12000 = 18000

) = 18,000 (split k = 2)

M[2, 4] = min(

k=2: M[2,2] + M[3,4] + 203030 = 0 + 36000 + 18000 = 54000,

k=3: M[2,3] + M[4,4] + 204030 = 24000 + 0 + 24000 = 48000

) = 48,000 (split k = 3)

Step 3: Compute chain length 4 (M[1, 4]):

k=1: M[1,1] + M[2,4] + 102030 = 0 + 48000 + 6000 = 54,000

k=2: M[1,2] + M[3,4] + 103030 = 6000 + 36000 + 9000 = 51,000

k=3: M[1,3] + M[4,4] + 104030 = 18000 + 0 + 12000 = 30,000 (MINIMAL)

Step 4: Final Answer & Optimal Parenthesization:

Minimum scalar multiplications = 30,000.

Optimal parenthesization: ((A1 (A2 A3)) * A4).

SOURCE TRANSPARENCY & CITATIONS

Primary Academic References & Exam Sources

Every concept in Notes From a B.Tech Brain is synthesized from authoritative academic texts, seminal peer-reviewed research, verified exam archives, and renowned university lectures.

Curated University Lecture Series
Introduction to Algorithms (4th Edition) ·
LECTURE SERIES
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Abdul Bari · Algorithms↗Instructor: Abdul Bari · Covers: Sorting, graph algorithms, dynamic programming, greedy, backtracking

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