ENGINEERING MATHEMATICS/Student Engineering Notebook
Page 04·notes
DIFFERENTIAL CALCULUS & MEAN VALUE THEOREMS—~28 MIN READ

Mean Value Theorems & Taylor-Maclaurin Series

“Rolle's, Lagrange's, Cauchy's MVT, Taylor polynomial approximations, and remainder formulas.”

1.Mean Value Theorems and Polynomial Approximations

Mean Value Theorems connect average rate of change over an interval to instantaneous rate of change at an interior point.

Geometric Meaning of LMVT: The secant line connecting (a, f(a)) and (b, f(b)) is parallel to the tangent line to the curve at some interior point (c, f(c)).

Root Isolation Corollary of Rolle's Theorem: Between any two real roots of a differentiable function f(x) = 0, there exists at least one real root of f'(x) = 0. Therefore, if f'(x) has at most k real roots, f(x) can have at most k + 1 real roots.

Taylor Series Expansion: Represents smooth functions as infinite polynomials:

f(x) = f(a) + f'(a)(x - a) + [f''(a) / 2!](x - a)^2 + ... + [f^{(n)}(a) / n!](x - a)^n + ...

notice this:— Checking Boundedness of Derivatives via LMVT

If |f'(x)| <= M for all x in [a, b], LMVT guarantees |f(b) - f(a)| <= M * |b - a|. GATE frequently tests this inequality to bound function values without integrating.

WORKED EXAM ANALYSIS · STEP-BY-STEP DERIVATION1 to 2 Marks (GATE Pattern)

2. Worked Problem: Finding the Point 'c' in LMVT

⚠️ Pitfall Warning:

If multiple roots for c arise, discard any values outside the open interval (a, b).

Problem [Original Practice Problem · Modeled on GATE Pattern]:

Verify Lagrange's Mean Value Theorem for f(x) = x^3 - 3x on the interval [0, 2], and find the value of c in (0, 2) that satisfies the theorem.

Step 1: Verify hypotheses:

f(x) is a polynomial, hence continuous on [0, 2] and differentiable on (0, 2).

Step 2: Compute f(a), f(b), and the average slope:

f(0) = 0^3 - 3(0) = 0

f(2) = 2^3 - 3(2) = 8 - 6 = 2

Average rate of change = [f(2) - f(0)] / (2 - 0) = [2 - 0] / 2 = 1.

Step 3: Differentiate f(x) and equate f'(c) to average slope:

f'(x) = 3x^2 - 3

f'(c) = 3c^2 - 3 = 1

3c^2 = 4 => c^2 = 4/3 => c = +/- 2 / sqrt(3).

Step 4: Check domain restriction c in (0, 2):

c = +2 / sqrt(3) ≈ 2 / 1.732 ≈ 1.155 in (0, 2).

c = -2 / sqrt(3) is rejected since -1.155 is not in (0, 2).

Conclusion: c = 2 / sqrt(3).

SOURCE TRANSPARENCY & CITATIONS

Primary Academic References & Exam Sources

Every concept in Notes From a B.Tech Brain is synthesized from authoritative academic texts, seminal peer-reviewed research, verified exam archives, and renowned university lectures.

Curated University Lecture Series
Principles of Mathematical Analysis (3rd Edition) ·
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