LINEAR ALGEBRA/Student Engineering Notebook
Page 11·notes
SINGULAR VALUE DECOMPOSITION (SVD) & PCA—~34 MIN READ

SVD Factorization, Eckart-Young Theorem & PCA

“A = U Sigma V^T, singular values sigma_i = sqrt(lambda_i), Eckart-Young rank-k truncation, and PCA dimensionality reduction.”

1.The Geometry of SVD & Principal Component Analysis

Singular Value Decomposition (SVD) generalizes eigendecomposition to non-square matrices of arbitrary shape m x n.

Geometric Meaning:

SVD decomposes any linear mapping into three sequential geometric operations: a rotation in the domain V^T, a coordinate stretching along orthogonal axes Sigma, and a rotation in the codomain U.

The Eckart-Young Low-Rank Approximation:

In data science, we frequently compress large datasets by discarding noisy dimensions. The best rank-k approximation in both Frobenius and spectral norm is the truncated SVD:

A_k = Sum_{i=1}^k sigma_i u_i v_i^T.

PCA as SVD:

Given a mean-centered data matrix X (where column means are 0), computing SVD X = U Sigma V^T directly reveals:

1. Principal component loading directions: Columns of V.

2. Low-dimensional projections: Z = X V = U Sigma.

3. Variances along principal axes: lambda_i = sigma_i^2 / (N - 1).

WORKED EXAM ANALYSIS · STEP-BY-STEP DERIVATION2 Marks (Original Practice Problem · Modeled on GATE DA Pattern)

2. Worked Practice Problem: Complete SVD & Rank-1 Approximation

⚠️ Pitfall Warning:

Use u_i = (1 / sigma_i) * A * v_i to ensure the left singular vectors have consistent signs with V.

Problem: Find the singular values, SVD matrices, and the optimal rank-1 approximation A_1 for matrix A = [ [3, 2, 2], [2, 3, -2] ] (size 2 x 3). What fraction of the total variance is captured by A_1?

Step 1: Compute A * A^T (size 2 x 2):

A A^T = [ [3, 2, 2], [2, 3, -2] ] [ [3, 2], [2, 3], [2, -2] ]

Entry (1, 1): 3^2 + 2^2 + 2^2 = 9 + 4 + 4 = 17.

Entry (1, 2): (3)(2) + (2)(3) + (2)(-2) = 6 + 6 - 4 = 8.

Entry (2, 2): 2^2 + 3^2 + (-2)^2 = 4 + 9 + 4 = 17.

A * A^T = [ [17, 8], [8, 17] ].

Step 2: Find eigenvalues of A * A^T:

det([ [17 - lambda, 8], [8, 17 - lambda] ]) = 0

(17 - lambda)^2 - 64 = 0 => 17 - lambda = +- 8.

lambda1 = 25, lambda2 = 9.

Step 3: Extract singular values:

sigma1 = sqrt(25) = 5.

sigma2 = sqrt(9) = 3.

Step 4: Find left singular vectors u1 and u2 (eigenvectors of A A^T):

For lambda1 = 25: (A A^T - 25*I) u1 = 0 => [ [-8, 8], [8, -8] ] u1 = 0 => u1 = [ 1/sqrt(2), 1/sqrt(2) ]^T.

For lambda2 = 9: (A A^T - 9*I) u2 = 0 => [ [8, 8], [8, 8] ] u2 = 0 => u2 = [ 1/sqrt(2), -1/sqrt(2) ]^T.

Step 5: Compute right singular vectors v1 and v2 via v_i = (1 / sigma_i) A^T u_i:

v1 = (1 / 5) [ [3, 2], [2, 3], [2, -2] ] [ 1/sqrt(2), 1/sqrt(2) ]^T

= (1 / (5sqrt(2))) [ 3 + 2, 2 + 3, 2 - 2 ]^T = (1 / (5sqrt(2))) [ 5, 5, 0 ]^T = [ 1/sqrt(2), 1/sqrt(2), 0 ]^T.

v2 = (1 / 3) [ [3, 2], [2, 3], [2, -2] ] [ 1/sqrt(2), -1/sqrt(2) ]^T

= (1 / (3sqrt(2))) [ 3 - 2, 2 - 3, 2 - (-2) ]^T = (1 / (3sqrt(2))) [ 1, -1, 4 ]^T.

Step 6: Compute optimal rank-1 approximation A_1 = sigma1 u1 v1^T:

A_1 = 5 [ 1/sqrt(2), 1/sqrt(2) ]^T [ 1/sqrt(2), 1/sqrt(2), 0 ]

A_1 = 5 (1/2) [ [1, 1, 0], [1, 1, 0] ] = [ [2.5, 2.5, 0], [2.5, 2.5, 0] ].

Step 7: Compute explained variance fraction:

Total variance (Frobenius norm squared): sigma1^2 + sigma2^2 = 25 + 9 = 34.

Variance captured by A_1 = sigma1^2 / (sigma1^2 + sigma2^2) = 25 / 34 ≈ 0.7353 (73.53%).

Conclusion: Singular values are {5, 3}, rank-1 approximation is A_1 = [ [2.5, 2.5, 0], [2.5, 2.5, 0] ], explaining 73.53% of total variance.

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Primary Academic References & Exam Sources

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